Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
Solution:
/**
* Note: The returned array must be malloced, assume caller calls free().
*/
int* twoSum(int* nums, int numsSize, int target) {
int i,j;
int *ans = malloc(2*sizeof(int));
for(i=0;i<numsSize;i++)
{
for(j=1;(j<numsSize && i!=j);j++)
{
if(nums[i] == (target - nums[j]))
{
ans[0] = i;
ans[1] = j;
}
}
}
return ans;
}
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